Base | Representation |
---|---|
bin | 10000000000111110101… |
… | …100000000101010101000 |
3 | 10220012202011010000201020 |
4 | 100000332230000222220 |
5 | 121012423204232412 |
6 | 2201331500052440 |
7 | 142340662066611 |
oct | 20007654005250 |
9 | 3805664100636 |
10 | 1100563352232 |
11 | 394823358953 |
12 | 159368534120 |
13 | 7ca237120a6 |
14 | 3b3a6230c08 |
15 | 1d96518018c |
hex | 1003eb00aa8 |
1100563352232 has 32 divisors (see below), whose sum is σ = 2752407967680. Its totient is φ = 366721172480.
The previous prime is 1100563352179. The next prime is 1100563352233. The reversal of 1100563352232 is 2322533650011.
It is a super-2 number, since 2×11005633522322 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1100563352193 and 1100563352202.
It is not an unprimeable number, because it can be changed into a prime (1100563352233) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8262444 + ... + 8394587.
It is an arithmetic number, because the mean of its divisors is an integer number (86012748990).
Almost surely, 21100563352232 is an apocalyptic number.
1100563352232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1100563352232 is an abundant number, since it is smaller than the sum of its proper divisors (1651844615448).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1100563352232 is a wasteful number, since it uses less digits than its factorization.
1100563352232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16659793 (or 16659789 counting only the distinct ones).
The product of its (nonzero) digits is 32400, while the sum is 33.
The spelling of 1100563352232 in words is "one trillion, one hundred billion, five hundred sixty-three million, three hundred fifty-two thousand, two hundred thirty-two".
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