11005656643 has 4 divisors (see below), whose sum is σ = 11106626080. Its totient is φ = 10904687208.

The previous prime is 11005656631. The next prime is 11005656677. The reversal of 11005656643 is 34665650011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34665650011 = 17 ⋅2039155883.

It is a cyclic number.

It is not a de Polignac number, because 11005656643 - 2¹⁷ = 11005525571 is a prime.

It is a super-3 number, since 3×11005656643³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11005653643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50484555 + ... + 50484772.

It is an arithmetic number, because the mean of its divisors is an integer number (2776656520).

Almost surely, 2^11005656643 is an apocalyptic number.

11005656643 is a deficient number, since it is larger than the sum of its proper divisors (100969437).

11005656643 is a wasteful number, since it uses less digits than its factorization.

11005656643 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100969436.

The product of its (nonzero) digits is 64800, while the sum is 37.

The spelling of 11005656643 in words is "eleven billion, five million, six hundred fifty-six thousand, six hundred forty-three".