Base | Representation |
---|---|
bin | 1010000000100111110100… |
… | …0110010111010100000111 |
3 | 1102222010220110211220010221 |
4 | 2200021331012113110013 |
5 | 2420304342042021321 |
6 | 35223555205325211 |
7 | 2214100052145046 |
oct | 240117506272407 |
9 | 42863813756127 |
10 | 11005805032711 |
11 | 3563599024a05 |
12 | 1298bb9a06807 |
13 | 61aac5ca8458 |
14 | 2a098051255d |
15 | 14144612de41 |
hex | a027d197507 |
11005805032711 has 2 divisors, whose sum is σ = 11005805032712. Its totient is φ = 11005805032710.
The previous prime is 11005805032681. The next prime is 11005805032723. The reversal of 11005805032711 is 11723050850011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11005805032711 - 25 = 11005805032679 is a prime.
It is a super-2 number, since 2×110058050327112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11005805032741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502902516355 + 5502902516356.
It is an arithmetic number, because the mean of its divisors is an integer number (5502902516356).
Almost surely, 211005805032711 is an apocalyptic number.
11005805032711 is a deficient number, since it is larger than the sum of its proper divisors (1).
11005805032711 is an equidigital number, since it uses as much as digits as its factorization.
11005805032711 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 34.
Adding to 11005805032711 its reverse (11723050850011), we get a palindrome (22728855882722).
The spelling of 11005805032711 in words is "eleven trillion, five billion, eight hundred five million, thirty-two thousand, seven hundred eleven".
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