11006132433 has 4 divisors (see below), whose sum is σ = 14674843248. Its totient is φ = 7337421620.

The previous prime is 11006132419. The next prime is 11006132471. The reversal of 11006132433 is 33423160011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11006132433 - 2⁸ = 11006132177 is a prime.

It is a super-2 number, since 2×11006132433² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11006132233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1834355403 + ... + 1834355408.

It is an arithmetic number, because the mean of its divisors is an integer number (3668710812).

Almost surely, 2^11006132433 is an apocalyptic number.

It is an amenable number.

11006132433 is a deficient number, since it is larger than the sum of its proper divisors (3668710815).

11006132433 is an equidigital number, since it uses as much as digits as its factorization.

11006132433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3668710814.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 11006132433 its reverse (33423160011), we get a palindrome (44429292444).

The spelling of 11006132433 in words is "eleven billion, six million, one hundred thirty-two thousand, four hundred thirty-three".