Base | Representation |
---|---|
bin | 10000000001000010101… |
… | …010010000001101101101 |
3 | 10220012220210112002221100 |
4 | 100001002222100031231 |
5 | 121013042240003433 |
6 | 2201342240353313 |
7 | 142342431433452 |
oct | 20010252201555 |
9 | 3805823462840 |
10 | 1100630000493 |
11 | 394857a3a761 |
12 | 159386915839 |
13 | 7ca3447912a |
14 | 3b3b101d829 |
15 | 1d96ae47b13 |
hex | 10042a9036d |
1100630000493 has 24 divisors (see below), whose sum is σ = 1595461540608. Its totient is φ = 731141685792.
The previous prime is 1100630000479. The next prime is 1100630000501. The reversal of 1100630000493 is 3940000360011.
1100630000493 is a `hidden beast` number, since 110 + 0 + 63 + 0 + 0 + 0 + 0 + 493 = 666.
It is not a de Polignac number, because 1100630000493 - 29 = 1100629999981 is a prime.
It is a super-2 number, since 2×11006300004932 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1100630000443) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7063996 + ... + 7218122.
It is an arithmetic number, because the mean of its divisors is an integer number (66477564192).
Almost surely, 21100630000493 is an apocalyptic number.
It is an amenable number.
1100630000493 is a deficient number, since it is larger than the sum of its proper divisors (494831540115).
1100630000493 is a wasteful number, since it uses less digits than its factorization.
1100630000493 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 156953 (or 156950 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 27.
The spelling of 1100630000493 in words is "one trillion, one hundred billion, six hundred thirty million, four hundred ninety-three", and thus it is an aban number.
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