11006453301434 has 4 divisors (see below), whose sum is σ = 16509679952154. Its totient is φ = 5503226650716.

The previous prime is 11006453301407. The next prime is 11006453301439. The reversal of 11006453301434 is 43410335460011.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10481050128025 + 525403173409 = 3237445^2 + 724847^2 .

It is a super-2 number, since 2×11006453301434² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11006453301394 and 11006453301403.

It is not an unprimeable number, because it can be changed into a prime (11006453301439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2751613325357 + ... + 2751613325360.

Almost surely, 2^{11006453301434} is an apocalyptic number.

11006453301434 is a deficient number, since it is larger than the sum of its proper divisors (5503226650720).

11006453301434 is an equidigital number, since it uses as much as digits as its factorization.

11006453301434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5503226650719.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 11006453301434 its reverse (43410335460011), we get a palindrome (54416788761445).

The spelling of 11006453301434 in words is "eleven trillion, six billion, four hundred fifty-three million, three hundred one thousand, four hundred thirty-four".