11006511143641 has 16 divisors (see below), whose sum is σ = 12373677388800. Its totient is φ = 9714072012480.

The previous prime is 11006511143599. The next prime is 11006511143653. The reversal of 11006511143641 is 14634111560011.

It is a cyclic number.

It is not a de Polignac number, because 11006511143641 - 2⁹ = 11006511143129 is a prime.

It is a super-3 number, since 3×11006511143641³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 11006511143597 and 11006511143606.

It is not an unprimeable number, because it can be changed into a prime (11006511143741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6954870 + ... + 8389471.

It is an arithmetic number, because the mean of its divisors is an integer number (773354836800).

Almost surely, 2^{11006511143641} is an apocalyptic number.

It is an amenable number.

11006511143641 is a deficient number, since it is larger than the sum of its proper divisors (1367166245159).

11006511143641 is a wasteful number, since it uses less digits than its factorization.

11006511143641 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15346776.

The product of its (nonzero) digits is 8640, while the sum is 34.

The spelling of 11006511143641 in words is "eleven trillion, six billion, five hundred eleven million, one hundred forty-three thousand, six hundred forty-one".