Base | Representation |
---|---|
bin | 1010000000101010111010… |
… | …0101110010000111100111 |
3 | 1102222020001100020111211121 |
4 | 2200022232211302013213 |
5 | 2420313042122240201 |
6 | 35224213430114411 |
7 | 2214126453561436 |
oct | 240125645620747 |
9 | 42866040214747 |
10 | 11006635352551 |
11 | 3563984794553 |
12 | 12991abaaba07 |
13 | 61abc9015a77 |
14 | 2a0a1c8d111d |
15 | 141493e949a1 |
hex | a02ae9721e7 |
11006635352551 has 2 divisors, whose sum is σ = 11006635352552. Its totient is φ = 11006635352550.
The previous prime is 11006635352491. The next prime is 11006635352593. The reversal of 11006635352551 is 15525353660011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11006635352551 - 27 = 11006635352423 is a prime.
It is a super-2 number, since 2×110066353525512 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11006635352498 and 11006635352507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11006635353551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5503317676275 + 5503317676276.
It is an arithmetic number, because the mean of its divisors is an integer number (5503317676276).
Almost surely, 211006635352551 is an apocalyptic number.
11006635352551 is a deficient number, since it is larger than the sum of its proper divisors (1).
11006635352551 is an equidigital number, since it uses as much as digits as its factorization.
11006635352551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 405000, while the sum is 43.
The spelling of 11006635352551 in words is "eleven trillion, six billion, six hundred thirty-five million, three hundred fifty-two thousand, five hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •