Base | Representation |
---|---|
bin | 1010000000101011000100… |
… | …1111010011001000000001 |
3 | 1102222020011102212011200001 |
4 | 2200022301033103020001 |
5 | 2420313140011240311 |
6 | 35224222054400001 |
7 | 2214130533361063 |
oct | 240126117231001 |
9 | 42866142764601 |
10 | 11006679790081 |
11 | 35639a7886088 |
12 | 1299202960001 |
13 | 61ac052a4371 |
14 | 2a0a2477b733 |
15 | 141497d214c1 |
hex | a02b13d3201 |
11006679790081 has 4 divisors (see below), whose sum is σ = 11018062086592. Its totient is φ = 10995297493572.
The previous prime is 11006679790063. The next prime is 11006679790097. The reversal of 11006679790081 is 18009797660011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11006679790081 - 29 = 11006679789569 is a prime.
It is a super-2 number, since 2×110066797900812 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11006679797081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5691146805 + ... + 5691148738.
It is an arithmetic number, because the mean of its divisors is an integer number (2754515521648).
Almost surely, 211006679790081 is an apocalyptic number.
It is an amenable number.
11006679790081 is a deficient number, since it is larger than the sum of its proper divisors (11382296511).
11006679790081 is an equidigital number, since it uses as much as digits as its factorization.
11006679790081 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11382296510.
The product of its (nonzero) digits is 1143072, while the sum is 55.
The spelling of 11006679790081 in words is "eleven trillion, six billion, six hundred seventy-nine million, seven hundred ninety thousand, eighty-one".
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