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110077073814661 is a prime number
BaseRepresentation
bin11001000001110101010000…
…111000011111010010000101
3112102202021011112112020110021
4121001311100320133102011
5103412000321344032121
61030040413135055141
732120543335240552
oct3101652070372205
9472667145466407
10110077073814661
113208a474512988
12104198113714b1
1349562ba0c7955
141d27a8a209a29
15cad555d6d641
hex641d50e1f485

110077073814661 has 2 divisors, whose sum is σ = 110077073814662. Its totient is φ = 110077073814660.

The previous prime is 110077073814647. The next prime is 110077073814809. The reversal of 110077073814661 is 166418370770011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90296194909761 + 19780878904900 = 9502431^2 + 4447570^2 .

It is an emirp because it is prime and its reverse (166418370770011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110077073814661 - 211 = 110077073812613 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110077073814599 and 110077073814608.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110077073814641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55038536907330 + 55038536907331.

It is an arithmetic number, because the mean of its divisors is an integer number (55038536907331).

Almost surely, 2110077073814661 is an apocalyptic number.

It is an amenable number.

110077073814661 is a deficient number, since it is larger than the sum of its proper divisors (1).

110077073814661 is an equidigital number, since it uses as much as digits as its factorization.

110077073814661 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1185408, while the sum is 52.

The spelling of 110077073814661 in words is "one hundred ten trillion, seventy-seven billion, seventy-three million, eight hundred fourteen thousand, six hundred sixty-one".