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11008113 = 33669371
BaseRepresentation
bin101001111111…
…100001110001
3202201021021220
4221333201301
510304224423
61031535253
7162365424
oct51774161
922637256
1011008113
116239616
12382a529
13238569c
1416679bb
15e769e3
hexa7f871

11008113 has 4 divisors (see below), whose sum is σ = 14677488. Its totient is φ = 7338740.

The previous prime is 11008111. The next prime is 11008117. The reversal of 11008113 is 31180011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11008113 - 21 = 11008111 is a prime.

It is a plaindrome in base 14.

It is a junction number, because it is equal to n+sod(n) for n = 11008092 and 11008101.

It is not an unprimeable number, because it can be changed into a prime (11008111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1834683 + ... + 1834688.

It is an arithmetic number, because the mean of its divisors is an integer number (3669372).

Almost surely, 211008113 is an apocalyptic number.

It is an amenable number.

11008113 is a deficient number, since it is larger than the sum of its proper divisors (3669375).

11008113 is an equidigital number, since it uses as much as digits as its factorization.

11008113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3669374.

The product of its (nonzero) digits is 24, while the sum is 15.

The square root of 11008113 is about 3317.8476456884. The cubic root of 11008113 is about 222.4526718339.

Adding to 11008113 its reverse (31180011), we get a palindrome (42188124).

The spelling of 11008113 in words is "eleven million, eight thousand, one hundred thirteen".

Divisors: 1 3 3669371 11008113