Base | Representation |
---|---|
bin | 1010000000110001000111… |
… | …1011111110011010000110 |
3 | 1102222101100111112210022100 |
4 | 2200030101323332122012 |
5 | 2420330000320130223 |
6 | 35225051050412530 |
7 | 2214215663040516 |
oct | 240142173763206 |
9 | 42871314483270 |
10 | 11008302114438 |
11 | 356465a615412 |
12 | 1299596131146 |
13 | 61b1034254c5 |
14 | 2a0b3a003846 |
15 | 141540480043 |
hex | a0311efe686 |
11008302114438 has 24 divisors (see below), whose sum is σ = 23894925147288. Its totient is φ = 3662725745952.
The previous prime is 11008302114421. The next prime is 11008302114457. The reversal of 11008302114438 is 83441120380011.
11008302114438 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 8 + 3 + 0 + 211 + 4 + 438 = 666.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 559014231 + ... + 559033922.
It is an arithmetic number, because the mean of its divisors is an integer number (995621881137).
Almost surely, 211008302114438 is an apocalyptic number.
11008302114438 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
11008302114438 is an abundant number, since it is smaller than the sum of its proper divisors (12886623032850).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11008302114438 is a wasteful number, since it uses less digits than its factorization.
11008302114438 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1118048708 (or 1118048705 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 36.
Adding to 11008302114438 its reverse (83441120380011), we get a palindrome (94449422494449).
The spelling of 11008302114438 in words is "eleven trillion, eight billion, three hundred two million, one hundred fourteen thousand, four hundred thirty-eight".
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