Base | Representation |
---|---|
bin | 10000000001010001101… |
… | …100101111010101011011 |
3 | 10220020120101021210012002 |
4 | 100001101230233111123 |
5 | 121014101332413431 |
6 | 2201423252311215 |
7 | 142351614146225 |
oct | 20012154572533 |
9 | 3806511253162 |
10 | 1100882310491 |
11 | 394977400a17 |
12 | 15943731250b |
13 | 7ca7481a0a2 |
14 | 3b3d673b415 |
15 | 1d9831863cb |
hex | 10051b2f55b |
1100882310491 has 2 divisors, whose sum is σ = 1100882310492. Its totient is φ = 1100882310490.
The previous prime is 1100882310461. The next prime is 1100882310529. The reversal of 1100882310491 is 1940132880011.
It is an a-pointer prime, because the next prime (1100882310529) can be obtained adding 1100882310491 to its sum of digits (38).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100882310491 is a prime.
It is a super-2 number, since 2×11008823104912 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100882310421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550441155245 + 550441155246.
It is an arithmetic number, because the mean of its divisors is an integer number (550441155246).
Almost surely, 21100882310491 is an apocalyptic number.
1100882310491 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100882310491 is an equidigital number, since it uses as much as digits as its factorization.
1100882310491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 38.
The spelling of 1100882310491 in words is "one trillion, one hundred billion, eight hundred eighty-two million, three hundred ten thousand, four hundred ninety-one".
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