Base | Representation |
---|---|
bin | 10000000001010101011… |
… | …011111011000111001011 |
3 | 10220020201202021022022121 |
4 | 100001111123323013023 |
5 | 121014213410324042 |
6 | 2201433412232111 |
7 | 142353305122042 |
oct | 20012533730713 |
9 | 3806652238277 |
10 | 1100945011147 |
11 | 3949a9836943 |
12 | 15945430b637 |
13 | 7ca84801377 |
14 | 3b400bbd559 |
15 | 1d98891e367 |
hex | 100556fb1cb |
1100945011147 has 2 divisors, whose sum is σ = 1100945011148. Its totient is φ = 1100945011146.
The previous prime is 1100945011141. The next prime is 1100945011151. The reversal of 1100945011147 is 7411105490011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100945011147 - 23 = 1100945011139 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100945011141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550472505573 + 550472505574.
It is an arithmetic number, because the mean of its divisors is an integer number (550472505574).
Almost surely, 21100945011147 is an apocalyptic number.
1100945011147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100945011147 is an equidigital number, since it uses as much as digits as its factorization.
1100945011147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 34.
The spelling of 1100945011147 in words is "one trillion, one hundred billion, nine hundred forty-five million, eleven thousand, one hundred forty-seven".
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