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11010100000127 is a prime number
BaseRepresentation
bin1010000000110111110100…
…0110010111010101111111
31102222112222210120211211012
42200031331012113111333
52420342141100001002
635225545313345435
72214311353600664
oct240157506272577
942875883524735
1011010100000127
1135653a2465558
1212999b826827b
1361b32ba550a7
142a0c6aac9a6b
151415e821bd52
hexa037d19757f

11010100000127 has 2 divisors, whose sum is σ = 11010100000128. Its totient is φ = 11010100000126.

The previous prime is 11010100000019. The next prime is 11010100000171. The reversal of 11010100000127 is 72100000101011.

It is a strong prime.

It is an emirp because it is prime and its reverse (72100000101011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11010100000127 - 216 = 11010099934591 is a prime.

It is a super-2 number, since 2×110101000001272 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11010108000127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505050000063 + 5505050000064.

It is an arithmetic number, because the mean of its divisors is an integer number (5505050000064).

Almost surely, 211010100000127 is an apocalyptic number.

11010100000127 is a deficient number, since it is larger than the sum of its proper divisors (1).

11010100000127 is an equidigital number, since it uses as much as digits as its factorization.

11010100000127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14, while the sum is 14.

Adding to 11010100000127 its reverse (72100000101011), we get a palindrome (83110100101138).

The spelling of 11010100000127 in words is "eleven trillion, ten billion, one hundred million, one hundred twenty-seven", and thus it is an aban number.