Base | Representation |
---|---|
bin | 1010000000110111110110… |
… | …1100100000101110000011 |
3 | 1102222120000111101220001222 |
4 | 2200031331230200232003 |
5 | 2420342201130000003 |
6 | 35225550311545255 |
7 | 2214311534600102 |
oct | 240157554405603 |
9 | 42876014356058 |
10 | 11010110000003 |
11 | 35653a8075614 |
12 | 12999bb68b22b |
13 | 61b330b4688a |
14 | 2a0c6c170039 |
15 | 1415e9044c38 |
hex | a037db20b83 |
11010110000003 has 2 divisors, whose sum is σ = 11010110000004. Its totient is φ = 11010110000002.
The previous prime is 11010109999921. The next prime is 11010110000069. The reversal of 11010110000003 is 30000001101011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11010110000003 is a prime.
It is not a weakly prime, because it can be changed into another prime (11010110000503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505055000001 + 5505055000002.
It is an arithmetic number, because the mean of its divisors is an integer number (5505055000002).
Almost surely, 211010110000003 is an apocalyptic number.
11010110000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11010110000003 is an equidigital number, since it uses as much as digits as its factorization.
11010110000003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 8.
Adding to 11010110000003 its reverse (30000001101011), we get a palindrome (41010111101014).
The spelling of 11010110000003 in words is "eleven trillion, ten billion, one hundred ten million, three", and thus it is an aban number.
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