Base | Representation |
---|---|
bin | 1010000000110111110110… |
… | …1100111011100100110011 |
3 | 1102222120000111121110222001 |
4 | 2200031331230323210303 |
5 | 2420342201142010003 |
6 | 35225550314154431 |
7 | 2214311535535564 |
oct | 240157554734463 |
9 | 42876014543861 |
10 | 11010110110003 |
11 | 35653a8140224 |
12 | 12999bb722a17 |
13 | 61b330b84974 |
14 | 2a0c6c19c16b |
15 | 1415e906761d |
hex | a037db3b933 |
11010110110003 has 2 divisors, whose sum is σ = 11010110110004. Its totient is φ = 11010110110002.
The previous prime is 11010110109997. The next prime is 11010110110009. The reversal of 11010110110003 is 30001101101011.
It is a balanced prime because it is at equal distance from previous prime (11010110109997) and next prime (11010110110009).
It is an emirp because it is prime and its reverse (30001101101011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11010110110003 - 213 = 11010110101811 is a prime.
It is not a weakly prime, because it can be changed into another prime (11010110110009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505055055001 + 5505055055002.
It is an arithmetic number, because the mean of its divisors is an integer number (5505055055002).
Almost surely, 211010110110003 is an apocalyptic number.
11010110110003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11010110110003 is an equidigital number, since it uses as much as digits as its factorization.
11010110110003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 10.
Adding to 11010110110003 its reverse (30001101101011), we get a palindrome (41011211211014).
The spelling of 11010110110003 in words is "eleven trillion, ten billion, one hundred ten million, one hundred ten thousand, three".
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