Base | Representation |
---|---|
bin | 11001000010001011101001… |
… | …100111000100110001100011 |
3 | 112102211120012201201210001222 |
4 | 121002023221213010301203 |
5 | 103412344033404001123 |
6 | 1030055430243245255 |
7 | 32122354112034563 |
oct | 3102135147046143 |
9 | 472746181653058 |
10 | 110101111000163 |
11 | 32099689914148 |
12 | 104223bb37982b |
13 | 495864b01373a |
14 | 1d28cca764da3 |
15 | cadeb12576c8 |
hex | 6422e99c4c63 |
110101111000163 has 2 divisors, whose sum is σ = 110101111000164. Its totient is φ = 110101111000162.
The previous prime is 110101111000121. The next prime is 110101111000183. The reversal of 110101111000163 is 361000111101011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110101111000163 is a prime.
It is not a weakly prime, because it can be changed into another prime (110101111000183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55050555500081 + 55050555500082.
It is an arithmetic number, because the mean of its divisors is an integer number (55050555500082).
Almost surely, 2110101111000163 is an apocalyptic number.
110101111000163 is a deficient number, since it is larger than the sum of its proper divisors (1).
110101111000163 is an equidigital number, since it uses as much as digits as its factorization.
110101111000163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 17.
Adding to 110101111000163 its reverse (361000111101011), we get a palindrome (471101222101174).
The spelling of 110101111000163 in words is "one hundred ten trillion, one hundred one billion, one hundred eleven million, one hundred sixty-three", and thus it is an aban number.
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