Search a number
-
+
110101120200202 = 255050560100101
BaseRepresentation
bin11001000010001011101010…
…001010001010111000001010
3112102211120020101001012011011
4121002023222022022320022
5103412344043232401302
61030055431212354134
732122354253163055
oct3102135212127012
9472746211035134
10110101120200202
113209969402828a
121042240247594a
13495864cbb5151
141d28ccba7ba9c
15cadeb1e735d7
hex6422ea28ae0a

110101120200202 has 4 divisors (see below), whose sum is σ = 165151680300306. Its totient is φ = 55050560100100.

The previous prime is 110101120200193. The next prime is 110101120200223. The reversal of 110101120200202 is 202002021101011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 98732820000721 + 11368300199481 = 9936439^2 + 3371691^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27525280050049 + ... + 27525280050052.

Almost surely, 2110101120200202 is an apocalyptic number.

110101120200202 is a deficient number, since it is larger than the sum of its proper divisors (55050560100104).

110101120200202 is an equidigital number, since it uses as much as digits as its factorization.

110101120200202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55050560100103.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 110101120200202 its reverse (202002021101011), we get a palindrome (312103141301213).

It can be divided in two parts, 1101011 and 20200202, that multiplied together give a palindrome (22240644604222).

The spelling of 110101120200202 in words is "one hundred ten trillion, one hundred one billion, one hundred twenty million, two hundred thousand, two hundred two".

Divisors: 1 2 55050560100101 110101120200202