11010302113 has 4 divisors (see below), whose sum is σ = 11010963348. Its totient is φ = 11009640880.

The previous prime is 11010302099. The next prime is 11010302123. The reversal of 11010302113 is 31120301011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31120301011 = 59 ⋅527462729.

It can be written as a sum of positive squares in 2 ways, for example, as 6250957969 + 4759344144 = 79063^2 + 68988^2 .

It is a cyclic number.

It is not a de Polignac number, because 11010302113 - 2¹⁷ = 11010171041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11010302093 and 11010302102.

It is not an unprimeable number, because it can be changed into a prime (11010302123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 304978 + ... + 339163.

It is an arithmetic number, because the mean of its divisors is an integer number (2752740837).

Almost surely, 2^11010302113 is an apocalyptic number.

It is an amenable number.

11010302113 is a deficient number, since it is larger than the sum of its proper divisors (661235).

11010302113 is an equidigital number, since it uses as much as digits as its factorization.

11010302113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 661234.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11010302113 its reverse (31120301011), we get a palindrome (42130603124).

The spelling of 11010302113 in words is "eleven billion, ten million, three hundred two thousand, one hundred thirteen".