Search a number
-
+
110106105504973 is a prime number
BaseRepresentation
bin11001000010010000010011…
…010011100110010011001101
3112102212001002210202220122121
4121002100103103212103031
5103412434301002124343
61030102014021012541
732122621636444234
oct3102202323462315
9472761083686577
10110106105504973
11320a0812108576
1210423373b54151
134958c6599a026
141d29241bd5b1b
15cae1a4975aed
hex6424134e64cd

110106105504973 has 2 divisors, whose sum is σ = 110106105504974. Its totient is φ = 110106105504972.

The previous prime is 110106105504959. The next prime is 110106105505069. The reversal of 110106105504973 is 379405501601011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 57729649588009 + 52376455916964 = 7598003^2 + 7237158^2 .

It is a cyclic number.

It is not a de Polignac number, because 110106105504973 - 221 = 110106103407821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110106105504953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55053052752486 + 55053052752487.

It is an arithmetic number, because the mean of its divisors is an integer number (55053052752487).

Almost surely, 2110106105504973 is an apocalyptic number.

It is an amenable number.

110106105504973 is a deficient number, since it is larger than the sum of its proper divisors (1).

110106105504973 is an equidigital number, since it uses as much as digits as its factorization.

110106105504973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 113400, while the sum is 43.

The spelling of 110106105504973 in words is "one hundred ten trillion, one hundred six billion, one hundred five million, five hundred four thousand, nine hundred seventy-three".