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1101099999953 is a prime number
BaseRepresentation
bin10000000001011110101…
…011001010001011010001
310220021010112220112222202
4100001132223022023101
5121020023044444303
62201501030212545
7142360166400332
oct20013653121321
93807115815882
101101099999953
11394a79276268
121594981b4155
137caaa958c15
143b417606289
151d997336c88
hex1005eaca2d1

1101099999953 has 2 divisors, whose sum is σ = 1101099999954. Its totient is φ = 1101099999952.

The previous prime is 1101099999911. The next prime is 1101099999973. The reversal of 1101099999953 is 3599999901011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1081624960144 + 19475039809 = 1040012^2 + 139553^2 .

It is a cyclic number.

It is not a de Polignac number, because 1101099999953 - 218 = 1101099737809 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1101099999953.

It is not a weakly prime, because it can be changed into another prime (1101099999973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550549999976 + 550549999977.

It is an arithmetic number, because the mean of its divisors is an integer number (550549999977).

Almost surely, 21101099999953 is an apocalyptic number.

It is an amenable number.

1101099999953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101099999953 is an equidigital number, since it uses as much as digits as its factorization.

1101099999953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7971615, while the sum is 65.

The spelling of 1101099999953 in words is "one trillion, one hundred one billion, ninety-nine million, nine hundred ninety-nine thousand, nine hundred fifty-three".