Base | Representation |
---|---|
bin | 10100100000100111… |
… | …01000011011000011 |
3 | 1001102101010202101221 |
4 | 22100103220123003 |
5 | 140022304000003 |
6 | 5020335535511 |
7 | 536601645553 |
oct | 122023503303 |
9 | 31371122357 |
10 | 11011000003 |
11 | 4740471303 |
12 | 217368a597 |
13 | 10662a9423 |
14 | 766535163 |
15 | 446a137bd |
hex | 2904e86c3 |
11011000003 has 2 divisors, whose sum is σ = 11011000004. Its totient is φ = 11011000002.
The previous prime is 11010999971. The next prime is 11011000043. The reversal of 11011000003 is 30000011011.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11011000003 - 25 = 11010999971 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11011000003.
It is not a weakly prime, because it can be changed into another prime (11011000043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505500001 + 5505500002.
It is an arithmetic number, because the mean of its divisors is an integer number (5505500002).
Almost surely, 211011000003 is an apocalyptic number.
11011000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011000003 is an equidigital number, since it uses as much as digits as its factorization.
11011000003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 7.
Adding to 11011000003 its reverse (30000011011), we get a palindrome (41011011014).
The spelling of 11011000003 in words is "eleven billion, eleven million, three", and thus it is an aban number and an uban number.
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