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110110020973 is a prime number
BaseRepresentation
bin110011010001100010…
…0011001010101101101
3101112012202102121202221
41212203010121111231
53301001131132343
6122330035515341
710645425510211
oct1464304312555
9345182377687
10110110020973
1142774266537
121940b758b51
13a4ca23b984
145487a62941
152ce6acb5ed
hex19a311956d

110110020973 has 2 divisors, whose sum is σ = 110110020974. Its totient is φ = 110110020972.

The previous prime is 110110020967. The next prime is 110110021027. The reversal of 110110020973 is 379020011011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 70253092809 + 39856928164 = 265053^2 + 199642^2 .

It is an emirp because it is prime and its reverse (379020011011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110110020973 - 213 = 110110012781 is a prime.

It is a super-3 number, since 3×1101100209733 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110110020473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055010486 + 55055010487.

It is an arithmetic number, because the mean of its divisors is an integer number (55055010487).

Almost surely, 2110110020973 is an apocalyptic number.

It is an amenable number.

110110020973 is a deficient number, since it is larger than the sum of its proper divisors (1).

110110020973 is an equidigital number, since it uses as much as digits as its factorization.

110110020973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378, while the sum is 25.

Adding to 110110020973 its reverse (379020011011), we get a palindrome (489130031984).

The spelling of 110110020973 in words is "one hundred ten billion, one hundred ten million, twenty thousand, nine hundred seventy-three".