Base | Representation |
---|---|
bin | 11001000010010100000001… |
… | …011001110110010111111011 |
3 | 112102212102102012100102210102 |
4 | 121002110001121312113323 |
5 | 103413020441112333313 |
6 | 1030103514235310015 |
7 | 32123122633225316 |
oct | 3102240131662773 |
9 | 472772365312712 |
10 | 110110100121083 |
11 | 320a2481a547a7 |
12 | 104240a98ab30b |
13 | 4959451454cba |
14 | 1d2950054797d |
15 | cae33a4d5a58 |
hex | 6425016765fb |
110110100121083 has 2 divisors, whose sum is σ = 110110100121084. Its totient is φ = 110110100121082.
The previous prime is 110110100121067. The next prime is 110110100121107. The reversal of 110110100121083 is 380121001011011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110110100121083 - 24 = 110110100121067 is a prime.
It is a super-2 number, since 2×1101101001210832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110110100121023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055050060541 + 55055050060542.
It is an arithmetic number, because the mean of its divisors is an integer number (55055050060542).
Almost surely, 2110110100121083 is an apocalyptic number.
110110100121083 is a deficient number, since it is larger than the sum of its proper divisors (1).
110110100121083 is an equidigital number, since it uses as much as digits as its factorization.
110110100121083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 20.
Adding to 110110100121083 its reverse (380121001011011), we get a palindrome (490231101132094).
The spelling of 110110100121083 in words is "one hundred ten trillion, one hundred ten billion, one hundred million, one hundred twenty-one thousand, eighty-three".
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