Base | Representation |
---|---|
bin | 11001000010010100111000… |
… | …010011001001011101010010 |
3 | 112102212111210101100120121121 |
4 | 121002110320103021131102 |
5 | 103413024332401023442 |
6 | 1030104145455312454 |
7 | 32123154515425423 |
oct | 3102247023113522 |
9 | 472774711316547 |
10 | 110111021111122 |
11 | 320a2904913199 |
12 | 1042430621b72a |
13 | 495956a1ba615 |
14 | 1d2958a9a964a |
15 | cae3912ab967 |
hex | 6425384c9752 |
110111021111122 has 4 divisors (see below), whose sum is σ = 165166531666686. Its totient is φ = 55055510555560.
The previous prime is 110111021111089. The next prime is 110111021111129. The reversal of 110111021111122 is 221111120111011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 58022482328001 + 52088538783121 = 7617249^2 + 7217239^2 .
It is a junction number, because it is equal to n+sod(n) for n = 110111021111096 and 110111021111105.
It is not an unprimeable number, because it can be changed into a prime (110111021111129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27527755277779 + ... + 27527755277782.
Almost surely, 2110111021111122 is an apocalyptic number.
110111021111122 is a deficient number, since it is larger than the sum of its proper divisors (55055510555564).
110111021111122 is an equidigital number, since it uses as much as digits as its factorization.
110111021111122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55055510555563.
The product of its (nonzero) digits is 8, while the sum is 16.
Adding to 110111021111122 its reverse (221111120111011), we get a palindrome (331222141222133).
The spelling of 110111021111122 in words is "one hundred ten trillion, one hundred eleven billion, twenty-one million, one hundred eleven thousand, one hundred twenty-two".
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