Base | Representation |
---|---|
bin | 11001000010010101000010… |
… | …111101100011101111100111 |
3 | 112102212112020211222010101121 |
4 | 121002111002331203233213 |
5 | 103413030214200012444 |
6 | 1030104215325434411 |
7 | 32123162120111311 |
oct | 3102250275435747 |
9 | 472775224863347 |
10 | 110111200000999 |
11 | 320a299689786a |
12 | 1042435610ba07 |
13 | 4959598293112 |
14 | 1d295a66547b1 |
15 | cae3a1d46084 |
hex | 642542f63be7 |
110111200000999 has 2 divisors, whose sum is σ = 110111200001000. Its totient is φ = 110111200000998.
The previous prime is 110111200000913. The next prime is 110111200001029. The reversal of 110111200000999 is 999000002111011.
It is a strong prime.
It is an emirp because it is prime and its reverse (999000002111011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110111200000999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110111200000099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055600000499 + 55055600000500.
It is an arithmetic number, because the mean of its divisors is an integer number (55055600000500).
Almost surely, 2110111200000999 is an apocalyptic number.
110111200000999 is a deficient number, since it is larger than the sum of its proper divisors (1).
110111200000999 is an equidigital number, since it uses as much as digits as its factorization.
110111200000999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 34.
The spelling of 110111200000999 in words is "one hundred ten trillion, one hundred eleven billion, two hundred million, nine hundred ninety-nine", and thus it is an aban number.
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