Base | Representation |
---|---|
bin | 10100100000101000… |
… | …01000001011000011 |
3 | 1001102101101100210112 |
4 | 22100110020023003 |
5 | 140022322130201 |
6 | 5020342421535 |
7 | 536603026655 |
oct | 122024101303 |
9 | 31371340715 |
10 | 11011130051 |
11 | 474054aa89 |
12 | 21737318ab |
13 | 106632368c |
14 | 76656a6d5 |
15 | 446a3c0bb |
hex | 2905082c3 |
11011130051 has 2 divisors, whose sum is σ = 11011130052. Its totient is φ = 11011130050.
The previous prime is 11011130023. The next prime is 11011130167. The reversal of 11011130051 is 15003111011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11011130051 - 214 = 11011113667 is a prime.
It is not a weakly prime, because it can be changed into another prime (11011130651) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505565025 + 5505565026.
It is an arithmetic number, because the mean of its divisors is an integer number (5505565026).
Almost surely, 211011130051 is an apocalyptic number.
11011130051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011130051 is an equidigital number, since it uses as much as digits as its factorization.
11011130051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15, while the sum is 14.
Adding to 11011130051 its reverse (15003111011), we get a palindrome (26014241062).
The spelling of 11011130051 in words is "eleven billion, eleven million, one hundred thirty thousand, fifty-one".
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