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1101113007 = 3379919937
BaseRepresentation
bin100000110100001…
…1010011010101111
32211201221100002020
41001220122122233
54223341104012
6301132401223
736200210001
oct10150323257
92751840066
101101113007
11515605555
12268916213
13147180477
14a634c371
1566a05a8c
hex41a1a6af

1101113007 has 8 divisors (see below), whose sum is σ = 1507830576. Its totient is φ = 714235392.

The previous prime is 1101113003. The next prime is 1101113051. The reversal of 1101113007 is 7003111011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1101113007 - 22 = 1101113003 is a prime.

It is a super-3 number, since 3×11011130073 (a number of 28 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1101113003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4959858 + ... + 4960079.

It is an arithmetic number, because the mean of its divisors is an integer number (188478822).

Almost surely, 21101113007 is an apocalyptic number.

1101113007 is a deficient number, since it is larger than the sum of its proper divisors (406717569).

1101113007 is an equidigital number, since it uses as much as digits as its factorization.

1101113007 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9919977.

The product of its (nonzero) digits is 21, while the sum is 15.

The square root of 1101113007 is about 33183.0228731501. The cubic root of 1101113007 is about 1032.6281602155.

Adding to 1101113007 its reverse (7003111011), we get a palindrome (8104224018).

The spelling of 1101113007 in words is "one billion, one hundred one million, one hundred thirteen thousand, seven".

Divisors: 1 3 37 111 9919937 29759811 367037669 1101113007