Base | Representation |
---|---|
bin | 10000000001011111100… |
… | …001011101000111111101 |
3 | 10220021011112200200112021 |
4 | 100001133201131013331 |
5 | 121020040220431331 |
6 | 2201502255240141 |
7 | 142360431361153 |
oct | 20013741350775 |
9 | 3807145620467 |
10 | 1101114233341 |
11 | 394a86307aa1 |
12 | 1594a0b19051 |
13 | 7cab08a0645 |
14 | 3b41946d3d3 |
15 | 1d9986e9211 |
hex | 1005f85d1fd |
1101114233341 has 2 divisors, whose sum is σ = 1101114233342. Its totient is φ = 1101114233340.
The previous prime is 1101114233327. The next prime is 1101114233377. The reversal of 1101114233341 is 1433324111011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1085774420025 + 15339813316 = 1042005^2 + 123854^2 .
It is a cyclic number.
It is not a de Polignac number, because 1101114233341 - 225 = 1101080678909 is a prime.
It is a super-2 number, since 2×11011142333412 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1101114293341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550557116670 + 550557116671.
It is an arithmetic number, because the mean of its divisors is an integer number (550557116671).
Almost surely, 21101114233341 is an apocalyptic number.
It is an amenable number.
1101114233341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101114233341 is an equidigital number, since it uses as much as digits as its factorization.
1101114233341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 1101114233341 its reverse (1433324111011), we get a palindrome (2534438344352).
The spelling of 1101114233341 in words is "one trillion, one hundred one billion, one hundred fourteen million, two hundred thirty-three thousand, three hundred forty-one".
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