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11011210000121 = 62983174828287
BaseRepresentation
bin1010000000111011111101…
…0000101011011011111001
31102222122212011020200120002
42200032333100223123321
52420401424230000441
635230251404442345
72214351022463402
oct240167720533371
942878764220502
1011011210000121
113565911a8aa21
12129a067b493b5
1361b4779c7616
142a0d342ac9a9
151416608cab9b
hexa03bf42b6f9

11011210000121 has 4 divisors (see below), whose sum is σ = 11011384891392. Its totient is φ = 11011035108852.

The previous prime is 11011210000097. The next prime is 11011210000127. The reversal of 11011210000121 is 12100001211011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11011210000121 - 214 = 11011209983737 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11011210000127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87351161 + ... + 87477126.

It is an arithmetic number, because the mean of its divisors is an integer number (2752846222848).

Almost surely, 211011210000121 is an apocalyptic number.

It is an amenable number.

11011210000121 is a deficient number, since it is larger than the sum of its proper divisors (174891271).

11011210000121 is an equidigital number, since it uses as much as digits as its factorization.

11011210000121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 174891270.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 11011210000121 its reverse (12100001211011), we get a palindrome (23111211211132).

The spelling of 11011210000121 in words is "eleven trillion, eleven billion, two hundred ten million, one hundred twenty-one", and thus it is an aban number.

Divisors: 1 62983 174828287 11011210000121