Base | Representation |
---|---|
bin | 1010000000111011111101… |
… | …0001001000101110010111 |
3 | 1102222122212011110210010021 |
4 | 2200032333101020232113 |
5 | 2420401424242320322 |
6 | 35230251411210011 |
7 | 2214351023503222 |
oct | 240167721105627 |
9 | 42878764423107 |
10 | 11011210120087 |
11 | 3565912062071 |
12 | 129a067ba6907 |
13 | 61b477a3a0c8 |
14 | 2a0d343005b9 |
15 | 1416609014c7 |
hex | a03bf448b97 |
11011210120087 has 2 divisors, whose sum is σ = 11011210120088. Its totient is φ = 11011210120086.
The previous prime is 11011210120073. The next prime is 11011210120109. The reversal of 11011210120087 is 78002101211011.
11011210120087 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11011210120087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11011210123087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505605060043 + 5505605060044.
It is an arithmetic number, because the mean of its divisors is an integer number (5505605060044).
Almost surely, 211011210120087 is an apocalyptic number.
11011210120087 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011210120087 is an equidigital number, since it uses as much as digits as its factorization.
11011210120087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 25.
Adding to 11011210120087 its reverse (78002101211011), we get a palindrome (89013311331098).
The spelling of 11011210120087 in words is "eleven trillion, eleven billion, two hundred ten million, one hundred twenty thousand, eighty-seven".
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