Base | Representation |
---|---|
bin | 1010000000111011111110… |
… | …0000111100110011000011 |
3 | 1102222122212110021101121112 |
4 | 2200032333200330303003 |
5 | 2420401431322444124 |
6 | 35230252040113535 |
7 | 2214351103650125 |
oct | 240167740746303 |
9 | 42878773241545 |
10 | 11011214265539 |
11 | 3565914433664 |
12 | 129a0694658ab |
13 | 61b47885bc37 |
14 | 2a0d34a9d215 |
15 | 141660e6e90e |
hex | a03bf83ccc3 |
11011214265539 has 2 divisors, whose sum is σ = 11011214265540. Its totient is φ = 11011214265538.
The previous prime is 11011214265497. The next prime is 11011214265581. The reversal of 11011214265539 is 93556241211011.
11011214265539 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (11011214265497) and next prime (11011214265581).
It is a cyclic number.
It is not a de Polignac number, because 11011214265539 - 216 = 11011214200003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11011214265496 and 11011214265505.
It is not a weakly prime, because it can be changed into another prime (11011214262539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505607132769 + 5505607132770.
It is an arithmetic number, because the mean of its divisors is an integer number (5505607132770).
Almost surely, 211011214265539 is an apocalyptic number.
11011214265539 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011214265539 is an equidigital number, since it uses as much as digits as its factorization.
11011214265539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 41.
The spelling of 11011214265539 in words is "eleven trillion, eleven billion, two hundred fourteen million, two hundred sixty-five thousand, five hundred thirty-nine".
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