Base | Representation |
---|---|
bin | 110011010001100110… |
… | …0101101010101100001 |
3 | 101112012220112022212212 |
4 | 1212203030231111201 |
5 | 3301002210400113 |
6 | 122330154331505 |
7 | 10645453154153 |
oct | 1464314552541 |
9 | 345186468785 |
10 | 110112200033 |
11 | 42775514710 |
12 | 19410429b95 |
13 | a4ca822764 |
14 | 548806cad3 |
15 | 2ce6dac0a8 |
hex | 19a332d561 |
110112200033 has 4 divisors (see below), whose sum is σ = 120122400048. Its totient is φ = 100102000020.
The previous prime is 110112200027. The next prime is 110112200041. The reversal of 110112200033 is 330002211011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 110112200033 - 26 = 110112199969 is a prime.
It is a super-2 number, since 2×1101122000332 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 110112199990 and 110112200017.
It is not an unprimeable number, because it can be changed into a prime (110112205033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5005099991 + ... + 5005100012.
It is an arithmetic number, because the mean of its divisors is an integer number (30030600012).
Almost surely, 2110112200033 is an apocalyptic number.
It is an amenable number.
110112200033 is a deficient number, since it is larger than the sum of its proper divisors (10010200015).
110112200033 is a wasteful number, since it uses less digits than its factorization.
110112200033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10010200014.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 110112200033 its reverse (330002211011), we get a palindrome (440114411044).
The spelling of 110112200033 in words is "one hundred ten billion, one hundred twelve million, two hundred thousand, thirty-three".
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