Base | Representation |
---|---|
bin | 10000000001100000000… |
… | …011101100111110001011 |
3 | 10220021012011120210202121 |
4 | 100001200003230332023 |
5 | 121020100020224042 |
6 | 2201503215512111 |
7 | 142360600602421 |
oct | 20014003547613 |
9 | 3807164523677 |
10 | 1101123211147 |
11 | 394a9038a173 |
12 | 1594a3b28637 |
13 | 7cab26c4b5b |
14 | 3b41a729111 |
15 | 1d9993be367 |
hex | 100600ecf8b |
1101123211147 has 2 divisors, whose sum is σ = 1101123211148. Its totient is φ = 1101123211146.
The previous prime is 1101123211109. The next prime is 1101123211171. The reversal of 1101123211147 is 7411123211011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1101123211147 is a prime.
It is a super-2 number, since 2×11011232111472 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1101123217147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550561605573 + 550561605574.
It is an arithmetic number, because the mean of its divisors is an integer number (550561605574).
Almost surely, 21101123211147 is an apocalyptic number.
1101123211147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101123211147 is an equidigital number, since it uses as much as digits as its factorization.
1101123211147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 25.
Adding to 1101123211147 its reverse (7411123211011), we get a palindrome (8512246422158).
The spelling of 1101123211147 in words is "one trillion, one hundred one billion, one hundred twenty-three million, two hundred eleven thousand, one hundred forty-seven".
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