11011310433 has 12 divisors (see below), whose sum is σ = 15914426580. Its totient is φ = 7336627296.

The previous prime is 11011310423. The next prime is 11011310461. The reversal of 11011310433 is 33401311011.

11011310433 is a `hidden beast` number, since 1 + 101 + 131 + 0 + 433 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 7983779904 + 3027530529 = 89352^2 + 55023^2 .

It is not a de Polignac number, because 11011310433 - 2¹² = 11011306337 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11011310413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 337398 + ... + 368591.

It is an arithmetic number, because the mean of its divisors is an integer number (1326202215).

Almost surely, 2^11011310433 is an apocalyptic number.

It is an amenable number.

11011310433 is a deficient number, since it is larger than the sum of its proper divisors (4903116147).

11011310433 is a wasteful number, since it uses less digits than its factorization.

11011310433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 707728 (or 707725 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 11011310433 its reverse (33401311011), we get a palindrome (44412621444).

The spelling of 11011310433 in words is "eleven billion, eleven million, three hundred ten thousand, four hundred thirty-three".