Base | Representation |
---|---|
bin | 10000000001100001001… |
… | …011110110011100110101 |
3 | 10220021020111011200210021 |
4 | 100001201023312130311 |
5 | 121020114340434331 |
6 | 2201505133125141 |
7 | 142361220424060 |
oct | 20014113663465 |
9 | 3807214150707 |
10 | 1101142124341 |
11 | 394aa0027a06 |
12 | 1594aa3297b1 |
13 | 7cab65b76ac |
14 | 3b41d04d8d7 |
15 | 1d99ada8211 |
hex | 100612f6735 |
1101142124341 has 8 divisors (see below), whose sum is σ = 1282192447104. Its totient is φ = 926027877840.
The previous prime is 1101142124333. The next prime is 1101142124347. The reversal of 1101142124341 is 1434212411011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1101142124341 - 23 = 1101142124333 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1101142124347) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1484018665 + ... + 1484019406.
It is an arithmetic number, because the mean of its divisors is an integer number (160274055888).
Almost surely, 21101142124341 is an apocalyptic number.
It is an amenable number.
1101142124341 is a deficient number, since it is larger than the sum of its proper divisors (181050322763).
1101142124341 is an equidigital number, since it uses as much as digits as its factorization.
1101142124341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2968038131.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 1101142124341 its reverse (1434212411011), we get a palindrome (2535354535352).
The spelling of 1101142124341 in words is "one trillion, one hundred one billion, one hundred forty-two million, one hundred twenty-four thousand, three hundred forty-one".
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