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11011525000053 = 317983219646241
BaseRepresentation
bin1010000000111101001000…
…0010010011101101110101
31102222200200002222100020020
42200033102002103231311
52420403100400000203
635230342540155353
72214361566105504
oct240172202235565
942880602870206
1011011525000053
113565a6387a046
12129a135538b59
1361b4c8047a06
142a0d6406883b
1514167d39e153
hexa03d2093b75

11011525000053 has 16 divisors (see below), whose sum is σ = 15561496953216. Its totient is φ = 6902163445760.

The previous prime is 11011524999997. The next prime is 11011525000057. The reversal of 11011525000053 is 35000052511011.

It is a cyclic number.

It is not a de Polignac number, because 11011525000053 - 225 = 11011491445621 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11011524999987 and 11011525000032.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11011525000057) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 109772988 + ... + 109873253.

It is an arithmetic number, because the mean of its divisors is an integer number (972593559576).

Almost surely, 211011525000053 is an apocalyptic number.

It is an amenable number.

11011525000053 is a deficient number, since it is larger than the sum of its proper divisors (4549971953163).

11011525000053 is a wasteful number, since it uses less digits than its factorization.

11011525000053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 219647244.

The product of its (nonzero) digits is 750, while the sum is 24.

Adding to 11011525000053 its reverse (35000052511011), we get a palindrome (46011577511064).

The spelling of 11011525000053 in words is "eleven trillion, eleven billion, five hundred twenty-five million, fifty-three", and thus it is an aban number.

Divisors: 1 3 17 51 983 2949 16711 50133 219646241 658938723 3733986097 11201958291 215912254903 647736764709 3670508333351 11011525000053