Base | Representation |
---|---|
bin | 1010000000111101001000… |
… | …0010010011101101110101 |
3 | 1102222200200002222100020020 |
4 | 2200033102002103231311 |
5 | 2420403100400000203 |
6 | 35230342540155353 |
7 | 2214361566105504 |
oct | 240172202235565 |
9 | 42880602870206 |
10 | 11011525000053 |
11 | 3565a6387a046 |
12 | 129a135538b59 |
13 | 61b4c8047a06 |
14 | 2a0d6406883b |
15 | 14167d39e153 |
hex | a03d2093b75 |
11011525000053 has 16 divisors (see below), whose sum is σ = 15561496953216. Its totient is φ = 6902163445760.
The previous prime is 11011524999997. The next prime is 11011525000057. The reversal of 11011525000053 is 35000052511011.
It is a cyclic number.
It is not a de Polignac number, because 11011525000053 - 225 = 11011491445621 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11011524999987 and 11011525000032.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11011525000057) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 109772988 + ... + 109873253.
It is an arithmetic number, because the mean of its divisors is an integer number (972593559576).
Almost surely, 211011525000053 is an apocalyptic number.
It is an amenable number.
11011525000053 is a deficient number, since it is larger than the sum of its proper divisors (4549971953163).
11011525000053 is a wasteful number, since it uses less digits than its factorization.
11011525000053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 219647244.
The product of its (nonzero) digits is 750, while the sum is 24.
Adding to 11011525000053 its reverse (35000052511011), we get a palindrome (46011577511064).
The spelling of 11011525000053 in words is "eleven trillion, eleven billion, five hundred twenty-five million, fifty-three", and thus it is an aban number.
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