Base | Representation |
---|---|
bin | 1010000000111101110100… |
… | …1000010000101111000011 |
3 | 1102222201011002011201012022 |
4 | 2200033131020100233003 |
5 | 2420403441021010313 |
6 | 35230413225152055 |
7 | 2214366316032365 |
oct | 240173510205703 |
9 | 42881132151168 |
10 | 11011711110083 |
11 | 3566049935292 |
12 | 129a18792b62b |
13 | 61b52777a9a8 |
14 | 2a0d80a72d35 |
15 | 14168e8b2c08 |
hex | a03dd210bc3 |
11011711110083 has 2 divisors, whose sum is σ = 11011711110084. Its totient is φ = 11011711110082.
The previous prime is 11011711110047. The next prime is 11011711110089. The reversal of 11011711110083 is 38001111711011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11011711110083 - 212 = 11011711105987 is a prime.
It is a super-2 number, since 2×110117111100832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11011711110089) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505855555041 + 5505855555042.
It is an arithmetic number, because the mean of its divisors is an integer number (5505855555042).
Almost surely, 211011711110083 is an apocalyptic number.
11011711110083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11011711110083 is an equidigital number, since it uses as much as digits as its factorization.
11011711110083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 26.
Adding to 11011711110083 its reverse (38001111711011), we get a palindrome (49012822821094).
The spelling of 11011711110083 in words is "eleven trillion, eleven billion, seven hundred eleven million, one hundred ten thousand, eighty-three".
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