11012000000117 has 2 divisors, whose sum is σ = 11012000000118. Its totient is φ = 11012000000116.

The previous prime is 11012000000083. The next prime is 11012000000129. The reversal of 11012000000117 is 71100000021011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6607336584676 + 4404663415441 = 2570474^2 + 2098729^2 .

It is a cyclic number.

It is not a de Polignac number, because 11012000000117 - 2³⁶ = 10943280523381 is a prime.

It is a super-3 number, since 3×11012000000117³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11012000000017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506000000058 + 5506000000059.

It is an arithmetic number, because the mean of its divisors is an integer number (5506000000059).

Almost surely, 2^{11012000000117} is an apocalyptic number.

It is an amenable number.

11012000000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

11012000000117 is an equidigital number, since it uses as much as digits as its factorization.

11012000000117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14, while the sum is 14.

Adding to 11012000000117 its reverse (71100000021011), we get a palindrome (82112000021128).

The spelling of 11012000000117 in words is "eleven trillion, twelve billion, one hundred seventeen", and thus it is an aban number.