Base | Representation |
---|---|
bin | 1010000000111110111110… |
… | …1010010000010010101011 |
3 | 1102222201221202012010010222 |
4 | 2200033233222100102223 |
5 | 2420410110113323201 |
6 | 35230504133000255 |
7 | 2214410112453245 |
oct | 240175752202253 |
9 | 42881852163128 |
10 | 11012022011051 |
11 | 3566199384836 |
12 | 129a253a8308b |
13 | 61b576cc4469 |
14 | 2a0db0083095 |
15 | 1416abd2691b |
hex | a03efa904ab |
11012022011051 has 2 divisors, whose sum is σ = 11012022011052. Its totient is φ = 11012022011050.
The previous prime is 11012022010909. The next prime is 11012022011099. The reversal of 11012022011051 is 15011022021011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11012022011051 - 210 = 11012022010027 is a prime.
It is a super-3 number, since 3×110120220110513 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11012022011251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506011005525 + 5506011005526.
It is an arithmetic number, because the mean of its divisors is an integer number (5506011005526).
Almost surely, 211012022011051 is an apocalyptic number.
11012022011051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012022011051 is an equidigital number, since it uses as much as digits as its factorization.
11012022011051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 11012022011051 its reverse (15011022021011), we get a palindrome (26023044032062).
The spelling of 11012022011051 in words is "eleven trillion, twelve billion, twenty-two million, eleven thousand, fifty-one".
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