Base | Representation |
---|---|
bin | 10000000001100100110… |
… | …001011110101101001011 |
3 | 10220021101200102221222122 |
4 | 100001210301132231023 |
5 | 121020230243221303 |
6 | 2201515123241455 |
7 | 142362551165156 |
oct | 20014461365513 |
9 | 3807350387878 |
10 | 1101202320203 |
11 | 395021001a57 |
12 | 15950651928b |
13 | 7cac5c0284b |
14 | 3b42703cc9d |
15 | 1d9a12e8e38 |
hex | 10064c5eb4b |
1101202320203 has 2 divisors, whose sum is σ = 1101202320204. Its totient is φ = 1101202320202.
The previous prime is 1101202320107. The next prime is 1101202320269. The reversal of 1101202320203 is 3020232021011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1101202320203 - 210 = 1101202319179 is a prime.
It is a super-2 number, since 2×11012023202032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1101202350203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550601160101 + 550601160102.
It is an arithmetic number, because the mean of its divisors is an integer number (550601160102).
Almost surely, 21101202320203 is an apocalyptic number.
1101202320203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101202320203 is an equidigital number, since it uses as much as digits as its factorization.
1101202320203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 1101202320203 its reverse (3020232021011), we get a palindrome (4121434341214).
The spelling of 1101202320203 in words is "one trillion, one hundred one billion, two hundred two million, three hundred twenty thousand, two hundred three".
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