11012054135035 has 4 divisors (see below), whose sum is σ = 13214464962048. Its totient is φ = 8809643308024.

The previous prime is 11012054134969. The next prime is 11012054135051. The reversal of 11012054135035 is 53053145021011.

11012054135035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11012054135035 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11012054134988 and 11012054135006.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1101205413499 + ... + 1101205413508.

It is an arithmetic number, because the mean of its divisors is an integer number (3303616240512).

Almost surely, 2^{11012054135035} is an apocalyptic number.

11012054135035 is a deficient number, since it is larger than the sum of its proper divisors (2202410827013).

11012054135035 is an equidigital number, since it uses as much as digits as its factorization.

11012054135035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2202410827012.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 11012054135035 its reverse (53053145021011), we get a palindrome (64065199156046).

The spelling of 11012054135035 in words is "eleven trillion, twelve billion, fifty-four million, one hundred thirty-five thousand, thirty-five".