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110121021120127 is a prime number
BaseRepresentation
bin11001000010011110001100…
…010110001001111001111111
3112102220110121022010200002111
4121002132030112021321333
5103413210322401321002
61030112522042234451
732123660363205553
oct3102361426117177
9472813538120074
10110121021120127
11320a7076633a46
12104262371b5a27
13495a4a1babc04
141d29c58b31863
15cae77916c3d7
hex64278c589e7f

110121021120127 has 2 divisors, whose sum is σ = 110121021120128. Its totient is φ = 110121021120126.

The previous prime is 110121021120107. The next prime is 110121021120163. The reversal of 110121021120127 is 721021120121011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110121021120127 - 223 = 110121012731519 is a prime.

It is a super-2 number, since 2×1101210211201272 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110121021120098 and 110121021120107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110121021120107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55060510560063 + 55060510560064.

It is an arithmetic number, because the mean of its divisors is an integer number (55060510560064).

Almost surely, 2110121021120127 is an apocalyptic number.

110121021120127 is a deficient number, since it is larger than the sum of its proper divisors (1).

110121021120127 is an equidigital number, since it uses as much as digits as its factorization.

110121021120127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112, while the sum is 22.

Adding to 110121021120127 its reverse (721021120121011), we get a palindrome (831142141241138).

The spelling of 110121021120127 in words is "one hundred ten trillion, one hundred twenty-one billion, twenty-one million, one hundred twenty thousand, one hundred twenty-seven".