Base | Representation |
---|---|
bin | 10100100000101111… |
… | …10101101111011101 |
3 | 1001102110012210121121 |
4 | 22100113311233131 |
5 | 140023044300013 |
6 | 5020415330541 |
7 | 536614221643 |
oct | 122027655735 |
9 | 31373183547 |
10 | 11012103133 |
11 | 4741055089 |
12 | 2173b20a51 |
13 | 10665a4575 |
14 | 766741193 |
15 | 446b8058d |
hex | 2905f5bdd |
11012103133 has 4 divisors (see below), whose sum is σ = 11309727580. Its totient is φ = 10714478688.
The previous prime is 11012103131. The next prime is 11012103161. The reversal of 11012103133 is 33130121011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6292138329 + 4719964804 = 79323^2 + 68702^2 .
It is a cyclic number.
It is not a de Polignac number, because 11012103133 - 21 = 11012103131 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11012103131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148812168 + ... + 148812241.
It is an arithmetic number, because the mean of its divisors is an integer number (2827431895).
Almost surely, 211012103133 is an apocalyptic number.
It is an amenable number.
11012103133 is a deficient number, since it is larger than the sum of its proper divisors (297624447).
11012103133 is an equidigital number, since it uses as much as digits as its factorization.
11012103133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 297624446.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11012103133 its reverse (33130121011), we get a palindrome (44142224144).
The spelling of 11012103133 in words is "eleven billion, twelve million, one hundred three thousand, one hundred thirty-three".
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