Base | Representation |
---|---|
bin | 1010000000111111010011… |
… | …1101101110001001110111 |
3 | 1102222202011221122020021202 |
4 | 2200033310331232021313 |
5 | 2420410300404001213 |
6 | 35230521032203115 |
7 | 2214412243035626 |
oct | 240176475561167 |
9 | 42882157566252 |
10 | 11012111000183 |
11 | 3566234635677 |
12 | 129a27983949b |
13 | 61b58c581257 |
14 | 2a0dbbc096bd |
15 | 1416b4a53b58 |
hex | a03f4f6e277 |
11012111000183 has 2 divisors, whose sum is σ = 11012111000184. Its totient is φ = 11012111000182.
The previous prime is 11012111000173. The next prime is 11012111000213. The reversal of 11012111000183 is 38100011121011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11012111000183 - 212 = 11012110996087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11012111000173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506055500091 + 5506055500092.
It is an arithmetic number, because the mean of its divisors is an integer number (5506055500092).
Almost surely, 211012111000183 is an apocalyptic number.
11012111000183 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012111000183 is an equidigital number, since it uses as much as digits as its factorization.
11012111000183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 20.
Adding to 11012111000183 its reverse (38100011121011), we get a palindrome (49112122121194).
The spelling of 11012111000183 in words is "eleven trillion, twelve billion, one hundred eleven million, one hundred eighty-three", and thus it is an aban number.
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