Base | Representation |
---|---|
bin | 11001000010011110010010… |
… | …001111011001011011000011 |
3 | 112102220110212012012220012101 |
4 | 121002132102033121123003 |
5 | 103413211023210340341 |
6 | 1030112535534011231 |
7 | 32123663003604145 |
oct | 3102362217313303 |
9 | 472813765186171 |
10 | 110121120011971 |
11 | 320a7117438942 |
12 | 10426264346b17 |
13 | 495a4b95251b3 |
14 | 1d29c67d14c95 |
15 | cae782ba3831 |
hex | 6427923d96c3 |
110121120011971 has 2 divisors, whose sum is σ = 110121120011972. Its totient is φ = 110121120011970.
The previous prime is 110121120011953. The next prime is 110121120012017. The reversal of 110121120011971 is 179110021121011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110121120011971 - 227 = 110120985794243 is a prime.
It is a super-2 number, since 2×1101211200119712 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110121120017971) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55060560005985 + 55060560005986.
It is an arithmetic number, because the mean of its divisors is an integer number (55060560005986).
Almost surely, 2110121120011971 is an apocalyptic number.
110121120011971 is a deficient number, since it is larger than the sum of its proper divisors (1).
110121120011971 is an equidigital number, since it uses as much as digits as its factorization.
110121120011971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 28.
Adding to 110121120011971 its reverse (179110021121011), we get a palindrome (289231141132982).
The spelling of 110121120011971 in words is "one hundred ten trillion, one hundred twenty-one billion, one hundred twenty million, eleven thousand, nine hundred seventy-one".
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