Base | Representation |
---|---|
bin | 1010000000111111010100… |
… | …0010011000011110010111 |
3 | 1102222202012000221022110001 |
4 | 2200033311002120132113 |
5 | 2420410301212101403 |
6 | 35230521114312131 |
7 | 2214412256315236 |
oct | 240176502303627 |
9 | 42882160838401 |
10 | 11012112222103 |
11 | 356623529a723 |
12 | 129a27a128647 |
13 | 61b58c8bb495 |
14 | 2a0dbc046b1d |
15 | 1416b4be5c1d |
hex | a03f5098797 |
11012112222103 has 4 divisors (see below), whose sum is σ = 11082253064440. Its totient is φ = 10941971379768.
The previous prime is 11012112222047. The next prime is 11012112222109. The reversal of 11012112222103 is 30122221121011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11012112222103 - 229 = 11011575351191 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11012112222109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35070420933 + ... + 35070421246.
It is an arithmetic number, because the mean of its divisors is an integer number (2770563266110).
Almost surely, 211012112222103 is an apocalyptic number.
11012112222103 is a deficient number, since it is larger than the sum of its proper divisors (70140842337).
11012112222103 is an equidigital number, since it uses as much as digits as its factorization.
11012112222103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70140842336.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 11012112222103 its reverse (30122221121011), we get a palindrome (41134333343114).
The spelling of 11012112222103 in words is "eleven trillion, twelve billion, one hundred twelve million, two hundred twenty-two thousand, one hundred three".
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