11012131433 has 2 divisors, whose sum is σ = 11012131434. Its totient is φ = 11012131432.

The previous prime is 11012131393. The next prime is 11012131441. The reversal of 11012131433 is 33413121011.

11012131433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7186461529 + 3825669904 = 84773^2 + 61852^2 .

It is a cyclic number.

It is not a de Polignac number, because 11012131433 - 2⁸ = 11012131177 is a prime.

It is not a weakly prime, because it can be changed into another prime (11012131033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506065716 + 5506065717.

It is an arithmetic number, because the mean of its divisors is an integer number (5506065717).

Almost surely, 2^11012131433 is an apocalyptic number.

It is an amenable number.

11012131433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11012131433 is an equidigital number, since it uses as much as digits as its factorization.

11012131433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 11012131433 its reverse (33413121011), we get a palindrome (44425252444).

The spelling of 11012131433 in words is "eleven billion, twelve million, one hundred thirty-one thousand, four hundred thirty-three".