Base | Representation |
---|---|
bin | 1010000000111111011000… |
… | …1111000110110000100111 |
3 | 1102222202020102210010122111 |
4 | 2200033312033012300213 |
5 | 2420410321334202011 |
6 | 35230523113341451 |
7 | 2214412622263321 |
oct | 240176617066047 |
9 | 42882212703574 |
10 | 11012132334631 |
11 | 356624568754a |
12 | 129a284a07887 |
13 | 61b593b10b9c |
14 | 2a0dc09a0611 |
15 | 1416b686a121 |
hex | a03f63c6c27 |
11012132334631 has 8 divisors (see below), whose sum is σ = 11611465649280. Its totient is φ = 10414773760248.
The previous prime is 11012132334629. The next prime is 11012132334647. The reversal of 11012132334631 is 13643323121011.
11012132334631 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11012132334631 - 21 = 11012132334629 is a prime.
It is a super-2 number, since 2×110121323346312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11012132334593 and 11012132334602.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11012132334691) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 493673611 + ... + 493695916.
It is an arithmetic number, because the mean of its divisors is an integer number (1451433206160).
Almost surely, 211012132334631 is an apocalyptic number.
11012132334631 is a deficient number, since it is larger than the sum of its proper divisors (599333314649).
11012132334631 is an equidigital number, since it uses as much as digits as its factorization.
11012132334631 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 987370133.
The product of its (nonzero) digits is 7776, while the sum is 31.
Adding to 11012132334631 its reverse (13643323121011), we get a palindrome (24655455455642).
The spelling of 11012132334631 in words is "eleven trillion, twelve billion, one hundred thirty-two million, three hundred thirty-four thousand, six hundred thirty-one".
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